Thus by substituting the corresponding values in the above equation, we get N=6.64
To meet the desired specifications, we select N=7.
63. Which of the following is true about the type-1 Chebyshev filter?
A. Equi-ripple behavior in passband
B. Monotonic characteristic in stopband
C. Equi-ripple behavior in passband & Monotonic characteristic in stopband
D. None of the mentioned
Answer: C
Type-1 Chebyshev filters are all-pole filters that exhibit equi-ripple behavior in the passband and a monotonic characteristic in the stopband.
64. Type-2 Chebyshev filters consists of ________
A. Only poles
B. Both poles and zeros
C. Only zeros
D. Cannot be determined
Answer: B
Type-1 Chebyshev filters are all-pole filters whereas the family of type-2 Chebyshev filters contains both poles and zeros.
65. Which of the following is false about the type-2 Chebyshev filters?
A. Monotonic behavior in the passband
B. Equi-ripple behavior in the stopband
C. Zero behavior
D. Monotonic behavior in the stopband
Answer: D
Type-2 Chebyshev filters exhibit equi-ripple behavior in the stopband and a monotonic characteristic in the passband.
66. The zeros of type-2 class of Chebyshev filters lies on ___________
A. Imaginary axis
B. Real axis
C. Zero
D. Cannot be determined
Answer: A
The zeros of this class of filters lie on the imaginary axis in the s-plane.
67. Which of the following defines a Chebyshev polynomial of order N, TN(x)?
A. cos(Ncos-1x) for all x
B. cosh(Ncosh-1x) for all x
C.cos(Ncos-1x), |x|≤1 cosh(Ncosh-1x), |x|>1
D. None of the mentioned
Answer: C
In order to understand the frequency-domain behavior of Chebyshev filters, it is of utmost importance to define a Chebyshev polynomial and then its properties. A Chebyshev polynomial of degree N is defined as
TN(x) = cos(Ncos-1x), |x|≤1
cosh(Ncosh-1x), |x|>1
68. The frequency response shown in the figure below belongs to which of the following filters?
A. Type-1 Chebyshev
B. Type-2 Chebyshev
C. Butterworth
D. Elliptical
Answer: B
Since the passband is monotonic in behavior and the stopband exhibit equi-ripple behavior, it is the magnitude square response of a type-2 Chebyshev filter.
69. What is the order of the type-2 Chebyshev filter whose magnitude square response is as shown in the following figure?
A. 2
B. 4
C. 6
D. 3
Answer: D
Since the magnitude square response of the type-2 Chebyshev filter, it has an odd number of maxima and minima in the stopband, the order of the filter is odd i.e., 3.
70. Which of the following is true about the magnitude square response of an elliptical filter?
A. Equi-ripple in passband
B. Equi-ripple in stopband
C. Equi-ripple in passband and stopband
D. None of the mentioned
Answer: C
An elliptical filter is a filter that exhibits equi-ripple behavior in both passband and stopband of the magnitude square response.
71. Bessel filters exhibit a linear phase response over the passband of the filter.
A. True
B. False
Answer: A
An important characteristic of the Bessel filter is the linear phase response over the passband of the filter. As a consequence, Bessel filters have a larger transition bandwidth, but their phase is linear within the passband.
71. The following frequency characteristic is for which of the following filter?
A. Type-2 Chebyshev filter
B. Type-1 Chebyshev filter
C. Butterworth filter
D. Bessel filter
Answer: A
The frequency characteristic given in the figure is the magnitude response of a 13-order type-2 Chebyshev filter.
72. Which of the following is the backward design equation for a low pass-to-high pass transformation?
A. ΩS=\(\frac{Ω_S}{Ω_u}\)
B. ΩS=\(\frac{Ω_u}{Ω’_S}\)
C. Ω’S=\(\frac{Ω_S}{Ω_u}\)
D. ΩS=\(\frac{Ω’_S}{Ω_u}\)
Answer: B
If Ωu is the desired passband edge frequency of the new high pass filter, then the transfer function of this new high pass filter is obtained by using the transformation s→Ωu/s. If ΩS and Ω’S are the stopband frequencies of prototype and transformed filters respectively, then the backward design equation is given by
ΩS=\(\frac{Ω_u}{Ω’_S}\)
73. Which of the following filter has a phase spectrum as shown in the figure?
A. Chebyshev filter
B. Butterworth filter
C. Bessel filter
D. Elliptical filter
Answer: D
The phase response given in the figure belongs to the frequency characteristic of a 7-order elliptic filter.
74. What is the passband edge frequency of an analog low pass normalized filter?
A. 0 rad/sec
B. 0.5 rad/sec
C. 1 rad/sec
D. 1.5 rad/sec
Answer: C
Let H(s) denote the transfer function of a low pass analog filter with a passband edge frequency ΩP equal to 1 rad/sec. This filter is known as the analog low pass normalized prototype.
75. Which of the following is a low pass-to-high pass transformation?
A. s → s / Ωu
B. s → Ωu / s
C. s → Ωu.s
D. none of the mentioned
Answer: B
The low pass-to-high pass transformation is simply achieved by replacing s by 1/s. If the desired high pass filter has the passband edge frequency Ωu, then the transformation is
s → Ωu / s.
76. Which of the following is the backward design equation for a low pass-to-low pass transformation?
A. ΩS=\(\frac{Ω_S}{Ω_u}\)
B. ΩS=\(\frac{Ω_u}{Ω’_S}\)
C. Ω’S=\(\frac{Ω_S}{Ω_u}\)
D. ΩS=\(\frac{Ω’_S}{Ω_u}\)
Answer: D
If Ωu is the desired passband edge frequency of the new low pass filter, then the transfer function of this new low pass filter is obtained by using the transformation s → s / Ωu. If ΩS and Ω’S are the stopband frequencies of prototype and transformed filters respectively, then the backward design equation is given by
ΩS=\(\frac{Ω’_S}{Ω_u}\)
77. If H(s) is the transfer function of an analog low pass normalized filter and Ωu is the desired passband edge frequency of a new low pass filter, then which of the following transformation has to be performed?
A. s → s / Ωu
B. s → s.Ωu
C. s → Ωu/s
D. None of the mentioned
Answer: A
If Ωu is the desired passband edge frequency of the new low pass filter, then the transfer function of this new low pass filter is obtained by using the transformation s → s / Ωu.
78. Which of the following is a low pass-to-band pass transformation?
A. s→\(\frac{s^2+Ω_u Ω_l}{s(Ω_u+Ω_l)}\)
B. s→\(\frac{s^2-Ω_u Ω_l}{s(Ω_u-Ω_l)}\)
C. s→\(\frac{s^2+Ω_u Ω_l}{s(Ω_u-Ω_l)}\)
D. s→\(\frac{s^2-Ω_u Ω_l}{s(Ω_u+Ω_l)}\)
Answer: C
If Ωu and Ωl are the upper and lower cutoff pass band frequencies of the desired bandpass filter, then the transformation to be performed on the normalized low pass filter is
s→\(\frac{s^2+Ω_u Ω_l}{s(Ω_u-Ω_l)}\)
80. If A=\(\frac{-Ω_1^2+Ω_u Ω_l}{Ω_1 (Ω_u-Ω_l)}\) and B=\(\frac{Ω_2^2-Ω_u Ω_l}{Ω_2 (Ω_u-Ω_l)}\), then which of the following is the backward design equation for a low pass-to-band pass transformation?
A. ΩS=|B|
B. ΩS=|A|
C. ΩS=Max{|A|,|B|}
D. ΩS=Min{|A|,|B|}
Answer: D
If Ωu and Ωl are the upper and lower cutoff pass band frequencies of the desired bandpass filter and Ω1 and Ω2 are the lower and upper cutoff stopband frequencies of the desired bandpass filter, then the backward design equation is
ΩS=Min{|A|,|B|}
where, A=\(\frac{-Ω_1^2+Ω_u Ω_l}{Ω_1 (Ω_u-Ω_l)}\) and B=\(\frac{Ω_2^2-Ω_u Ω_l}{Ω_2 (Ω_u-Ω_l)}\).