Ques 41. A 4-pole, the 3-phase induction motor is running at 4% slip at full load. If the speed of the motor is 750 rpm, the supply frequency is
50/3 Hz
26 Hz✔
50 Hz
60 Hz
Nr = 750 RPM
s = 0.04
Since Nr = Ns(1 – s)
= 750 = Ns(1 – 0.04)
Ns = 781.25 RPM
Now synchronous speed of motor
Ns = 120f/P
781.25 = 120f/4
f = 26.04 Hz
Ques 42. An oscillator uses
Positive feedback✔
Negative feedback
Both positive and negative feedback
No feedback
Positive feedback is used to have more gain. For oscillator, the gain should be at maximum to have sustained oscillations
Ques 43. Permeance is analogous to
Conductance✔
Reluctance
Inductance
Resistance
In a magnetic circuit, permeance is a measure of the quantity of magnetic flux for a number of current-turns. A magnetic circuit almost acts as though the flux is ‘conducted’, therefore permeance is larger for large cross-sections of a material and smaller for longer lengths. This concept is analogous to electrical conductance in the electric circuit.
Ques 44. A wire has a resistance 10Ω . It is stretched by one-tenth of its original length. Then its resistance will be
10Ω
12.1Ω✔
9Ω
11Ω
Resistance of a wire
R = ρl/A …………..1
where ρ is resistivity of the material
L is length in meters
A is cross-sectional area in m²
R’ = ρl’/A’……………..2
Now length of wire is stretched to 1/10 of its original length
l’ = l + l/10 = 11l/10
l’/l = 11/10
Since On stretching, Volume will be constant
lA = l’A’
A’/A = l/l’
from equation 1 & 2
R/R’ = lA’/l’A
R’ = R x 121/100
R’ = 1.21 x R = 1.21 x 10 = 12.1Ω
Ques 45. Potential transformer are used
To measure high a.c. voltage
To measure high d.c. voltage
Both (1) and (2)
A protective devicein high voltage circuits✔
Voltage transformers (VT), also called potential transformers (PT), are a parallel connected type of instrument transformer. They are used in the electrical power system for stepping down the system voltage to a safe value which can be fed to low ratings meters and relays.
Ques 46. A three-phase power transformer is provided with star-delta connections. In order to protect against fault, connection for current transformer should be in
Star-star
Delta-star✔
Delta-delta
Star-delta
The currents on the two sides of a 3-phase transformer in general differ in both magnitude and phase. The CT connection must compensate for these differences, as a percentage relay must compare currents which, under normal conditions, are identical (in magnitude and phase). In star/star or delta/delta transformers, the currents on the two sides have the same phase angle, the three CTs on both sides are, therefore, identically connected (star or delta) and an appropriate choice of CT ratios would be sufficient for magnitude equalization.
In case of a star/delta transformer, the currents on the two sides also differ in phase by 30°. This is compensated by connecting CTs in Delta on the star side, and in star on the delta side of the transformer
Ques 47. For active region operation of NPN transistor
Emitter is positive with respect to base
Emitter is –ve with respect to base✔
Emitter is at same voltage as base
Base is at same voltage as collector
The voltage between the Base and Emitter ( VBE ), is positive at the Base and negative at the Emitter because for an NPN transistor, the Base terminal is always positive with respect to the Emitter.
In electrical braking method, the stored energy of rotating part is converted into electrical energy and dissipated by the resistance in the form of heat or returned to the supply.
Advantages of Electrical Braking
Electric braking is fast and cheap.
Mechanical Braking due to excessive wear on the braking blocks or braking lining needs frequent and costly replacement and also due to wear and tear increase the maintenance cost. In electric braking, there is no maintenance cost like replaced brake shoes periodically.
In electric braking negligible amount of heat is generated.
In some cases of electrical braking, we can return about 60 to 80% of the kinetic and potential energy of the apparatus back to the line which is not possible with mechanical braking
Ques 49. A single phase motor is made-starting by the addition of a
Running winding
Starting winding✔
Electric starter
Auto-transformer
In order for an induction motor to be rotated, there should be rotating magnetic. In case of single phase motor during the positive half cycle, the rotor will rotate in one direction and in the negative half cycle, it rotates opposite to that. So the net torque developed is zero and hence single phase induction motor is not self-starting.
In order to self-start a single phase induction motor one must create a rotating magnetic field on the stator. Hence, the single phase motor needs an auxiliary winding which produces two magnetic fields displaced in time which provides a magnetic field and used to create the torque needed to start a single phase induction motor
Ques 50. To increase the range of a voltmeter
A low resistance is connected in series
A low resistance is connected in parallel
A high resistance is connected in series✔
A high resistance is connected in parallel
To increase the range of a voltmeter, the high-value resistance should be connected in series
The logic is that, if we increase the resistance, less current will flow as the voltmeter is connected in parallel to the supply voltage. This results in the decrease in the signal current for the voltmeter to process. [For analog voltmeter, the decrease in current leads to less deflection of the needle.] Thus, by re-calibrating the scale, the range of voltmeter is increased.
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4 thoughts on “SSC JE 2010 Electrical question paper with Solution”
manoj
plzz upload the full paper with solutions
admin
@ manoj till 2010 there was the combine paper of mechanical and electrical in ssc je that means 50 question of each respective branch ..so it is a full paper with solution
manoj
please upload the full paper with solutions…………
Surya
Question number 10 last line can’t understand 1/10=1/30+1/s
plzz upload the full paper with solutions
@ manoj till 2010 there was the combine paper of mechanical and electrical in ssc je that means 50 question of each respective branch ..so it is a full paper with solution
please upload the full paper with solutions…………
Question number 10 last line can’t understand 1/10=1/30+1/s