Using an electronic bridge compensator for melling
The only type of meter used in modern electronics instruments is the moving coil or d’Arsonval. This equipment is accurate and Robust and may be obtained with extremely sensitive movements.
To measure resistance a known EMF is applied in series with the meter and the resistor, and Ohm’s law is used to perform the calibration. A protective resistor is placed in series with the meter, so that if the unknown resistance should, in fact, be zero, the meter will read the only full scale, instead of passing a destructively large current. The value of the protective resistor is subtracted in each case from the total calculated resistance to obtain the unknown resistance.
Ques 42. If span length is doubled with no change in other factors, the sag of the line will become?
0.5 times
4 times
8 times
2 times
The relation between sag or deflection and span length is
d = wL2/8T
Where d = deflection
L = span length
T = Tension
If the length is double and all the factors remain constant then
d1 = 22
d1 = 4d
Hence if the length is doubled the sag of the line will become 4 times
Ques 43. A linear circuit is one whose parameters
Do not change with voltage and current✔
Change with change in the voltage
Change with change in the current
None of the above
A linear circuit is an electric circuit in which circuit parameters (Resistance, inductance, capacitance, waveform, frequency etc) are constant. In other words, a circuit whose parameters are not changed with respect to Current and Voltage is called Linear Circuit.
Ques 44. A 200 V lamp takes a current of 1A, it produces a total flux of 2860 lumens. The efficiency of the lamp is?
10.9 lumens /W
9.9 lumens /W
8.9 lumens/W
14.3 lumens/W✔
Lamp efficiency is given as
η = lumen/ VIcosΦ
= 2860/200 x 1
= 14.3 lumens/W
Ques 45. The unit for permeability is
Wb/At × m
At/m
Wb
At/Wb
In electromagnetism, permeability is the measure of the ability of a material to support the formation of a magnetic field within itself. Hence, it is the degree of magnetization that a material obtains in response to an applied magnetic field.
Reluctance in the magnetic circuit
R = l/µA
Where l = length in meter
µ = Permeability of the material —————1
Also, Reluctance in magnetic circuit is the ratio of m.m.f and flux and the SI unit is amp.turn/Weber……..2
From equation 1 permeability of the material is given as
µ = l/aR
= meter/(meter2 x amp.turns/Weber)
= wb/At × m
Ques 46. An alternator is supplying a load of 300 kW at a power factor of 0.6 lagging. If the power factor is raised to unity, How many more kW can the alternator supply?
300 kW
100 kW
150 kW
200 kW✔
PF = active power/apparent power. So from question
0.6=300/apparent power.
Apparent power=500 Kva.
At unity power factor, active power=apparent power. So active power=500kw. So you will get an additional 200kw at unity power factor
Ques 47. Leakage flux in a transformer occurs because:
The applied voltage is sinusoidal
Air is not a good magnetic insulator✔
The transformer is not an efficient device
Iron core has high permeability
Leakage Flux
The flux that does not pass through the air gap or useful part of the magnetic circuit is called as leakage flux since air is the bad magnetic insulator, therefore, it is a common phenomenon in the transformer.
Ques 48. Each of the following statements regarding a shaded pole motor is correct except
It has high starting torque✔
Its direction of rotation is from the unshaded pole to the shaded pole portion of the poles
It has a very poor power factor
It has very high efficiency
The shaded-pole motor is the original type of AC single-phase induction motor. A shaded-pole motor is a small squirrel-cage motor in which the auxiliary winding is composed of a copper ring or bar surrounding a portion of each pole. This auxiliary single-turn winding is called a shading coil. Since the phase angle between the shaded and unshaded sections is small, shaded pole motors produce only a small starting torque relative to torque at full speed.
The shaded pole motor has the lowest starting torque as compared to all single-phase induction motors.
Ques 49. Which of the following fault is comes under symmetrical fault?
LLLG fault✔
LG fault
LL fault
LLG fault
Asymmetrical fault gives rise to symmetrical fault currents that are displaced by 120° each other. The symmetrical fault is also called the balanced fault. This fault occurs when all three phases are simultaneously short-circuited. Two kinds of symmetrical faults include line to line (L-L-L) and line to line to ground (L-L-L-G).
Ques 50. The no-load input power to a transformer is practically equal to ______ loss in the transformer
Windage
Eddy current
Copper
Iron✔
At no load practical transformer, primary copper loss I02R is very small and this loss may be neglected. Hence, the primary no-load input power of a practical transformer is equal to the iron loss.
29 thoughts on “SSC JE 2015 Electrical question paper with solution”
sweeti saini
Ques 58. An active elements in the circuit is one
Dissipates energy✔
Receives Energy
Both receives and supplies
Supplies Energy
sir,
active elements supplies the energy into the ckt and passive elements dissipates the energy.
plz check this concept it is right or wrong?
admin
You are right sweeti saini . Actually, the explanation of the answer is right but i Ticked the wrong option… Thank You
Ques 58. An active elements in the circuit is one
Dissipates energy✔
Receives Energy
Both receives and supplies
Supplies Energy
sir,
active elements supplies the energy into the ckt and passive elements dissipates the energy.
plz check this concept it is right or wrong?
You are right sweeti saini . Actually, the explanation of the answer is right but i Ticked the wrong option… Thank You
Give me a answer for 22nd question plz..
sir pls mail me- explanation for qstn no.22
sir can you please explain 22 no question??
Sir..please give me earlier pdf.. previous years ssc je all paper 2 conventional papers for electrical …