Ques 51. The peak value of the output voltage of the half-wave rectifier is 100 V. The r.m.s value of the half-wave rectifier output voltage will be
100 V
50 V
70.7 V
35.35 V
Answer.2. 50V
Explanation:
RMS value of Half wave Rectifier is given as
VRms = Vm / 2
= 100 / 2
= 50 V
Ques 52. The given circuit represents a
Monostable multivibrator
Astable multivibrator
Schmitt trigger
Bistable multivibrator
Answer.3. Schmitt trigger
Explanation:
A Schmitt trigger is a device (or the input portion of a device) that has separate thresholds for a rising signal and a falling signal. It is a positive feedback circuit that holds the output level till the input sig the al to the comparator is higher than the threshold.
The positive feedback is introduced by adding a part of the output voltage to the input voltage.
Ques 53. The input resistance of a FET is of the order of
100 Ω
10 kΩ
1 MΩ
100 MΩ
Answer.4. 100 MΩ
Explanation:
The field-effect transistor (FET) is a transistor that uses an electric field to control the electrical behavior of the device. FETs are also known as unipolar transistors since they involve the single-carrier-type operation.
FET has a high gate to main current resistance, on the order of 100 MΩ or more, thus providing a high degree of isolation between control and flow.
FET has a negative temperature coefficient of resistance and hence has better stability against the temperature.
Ques 54. In a series, R-L circuit supplied from a sinusoidal voltage source, the voltage across R and L is 3V and 4V respectively. The supply voltage is then
7 V
1 V
3.5 V
5 V
Answer.4. 5V
Explanation:
Ques 55. If the insulation resistance of a 2m long sample of a cable is 10 MΩ, then the 8m sample of the same will have an insulation resistance of
40 MΩ
2.5 MΩ
2 MΩ
5.5 MΩ
Answer.2. 2.5 MΩ
Explanation:
Insulation resistance Riis given as
Where R is the radius of the cable
r is the radius of the Core
The insulation resistance varies inversely with the length
As per this question, we use only one conductor so the radius of the conductor, radius of insulation, and resistivity of the conductor is constant.
Now the formula become,
R=K/L
we put the value,
R1 x L1 = R2 x L2;
2 x 10 = R2 x 8
R2 = 2.5 MΩ
Ques 56. An inductor is supplied from a sinusoidal voltage source. The magnetic field energy in the inductor changes from the peak value to the minimum value in 10 msec. The supply frequency is
50 Hz
25 Hz
1 Hz
100 Hz
Answer.2. 25 Hz
Explanation:
For a quarter part of wave pulse energy going down to the maximum value to minimum value. i,e
Ques 57. Two 2000 Ω, 2-watt resistors are connected in parallel. Their combined resistance value and wattage rating are
1000 Ω, 2 watt
1000 Ω, 4 watt
2000 Ω, 4 watt
2000 Ω, 2 watt
Answer.2. 1000 Ω, 4 watt
Explanation:
When two resistance R1 and R2 are connected in parallel, the resulting resistance is (R1 x R2) / (R1 + R2).
(2000 x 2000) / (2000 + 2000)
= 1000 Ω
The wattage of Resistor In Combination
The total wattage of a combination of resistance is always equal to the sum of the individual wattages of the resistor irrespective of whether the combination is series-connected or parallel connected. This is because the total physical size of the combination increases with the addition of the resistance.
Therefore the total wattage for the above question will be 2W + 2W = 4W
Hence the answer will be 1000 ohm and 4 watts.
Ques 58. We have three resistances each of values 1 Ω, 2 Ω, and 3 Ω. If all the resistances are to be connected in a circuit, how many different values of equivalent resistance are possible?
Five
Six
Seven
Eight
Answer.4. Eight
Explanation:
Ques 59. One B.O.T unit is
100 kWh
10 kWh
1 kWh
0.1 kWh
Answer.3. 1 kWh
Explanation:
Board of Trade Unit(B.O.T)
Board of Trade Unit(B.O.T) – a unit of energy equal to the work done by a power of 1000 watts operating for one hour
1 kWh = 1 BOT Unit
Ques 60. An electric heater draws 1000 watts from a 250 V source. The power drawn from a 200 V source is
800 W
640 W
1000 W
1562.5 W
Answer.2. 640 W
Explanation:
The heater draws 1000W of power when connected to a 250V source.
Assume the resistance of the heating element to possess a value R.
Then, the power drawn by the heater Power is given by
Hi admin,
Can you pls mail me the ssc JE previous year paper with solution by mail ([email protected])
Will be highly thankful for the favour.
SSC JE electrical previous years paper with solution
Check your mail @Sumit Abrol
Hi admin,
Waiting for the previous years JE electrical paper PDF mail pls support .
Sorry for the delay Sumit check your mail box now
Thanks for the support
Ok i will give you the pdf by tommorow @Sumit Abrol
Nice collection sir .plz send me all paper in pdf
Sir,
Please deeply explain question number:-98.
Bro please provide questions number 98 with solutions